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Solving SSA Triangles
"SSA" means "Side, Side, Angle"
"SSA" is when we know two sides and an angle that is not the angle between the sides. |
Example 1
In this triangle we know
- angle B = 31°
- b = 8
- and c = 13
In this case, we can use The Law of Sines first to find angle C:
sin(C)/c = sin(B)/b
sin(C)/13 = sin(31°)/8
sin(C) = (13×sin(31°))/8
sin(C) = 0.8369...
C = sin−1(0.8369...)
C = 56.818...°
C = 56.8° to one decimal place (*see below)
Next, we can use the three angles add to 180° to find angle A:
A = 180° − 31° − 56.818...°
A = 92.181...° = 92.2° to one decimal place
Now we can use The Law of Sines again to find a:
a/sin(A) = b/sin(B)
a/sin(92.181...°) = 8/sin(31°)
Notice that we didn't use A = 92.2°, that angle is rounded to 1 decimal place. It's much better to use the unrounded number 92.181...° which should still be on our calculator from the last calculation.
a = (sin(92.181...°) × 8)/sin(31°)
a = 15.52 to 2 decimal places
So, we have completely solved the triangle ...
... or have we?
* Back when we calculated:
C = sin−1(0.8369...)
C = 56.818...°
We didn't think that sin−1(0.8369...) might have two answers (see Law of Sines)
The other answer for C is 180° − 56.818...°
Here you can see why we have two possible answers:
By swinging side "8" left and right we can
join up with side "a" in two possible locations.
So let's go back and continue our example:
The other possible angle is:
C = 180° − 56.818...°
C = 123.2° to one decimal place
With a new value for C we will have new values for angle A and side a
Use "the three angles add to 180°" to find angle A:
A = 180° − 31° − 123.181...°
A = 25.818...°
A = 25.8° to one decimal place
Now we can use The Law of Sines again to find a:
a/sin(A) = b/sin(B)
a/sin(25.818...°) = 8/sin(31°)
a = (sin(25.818...°)×8)/sin(31°)
a = 6.76 to 2 decimal places
So the two sets of answers are:
C = 56.8°, A = 92.2°, a = 15.52
C = 123.2°, A = 25.8°, a = 6.76
Example 2
This is also an SSA triangle.
In this triangle we know angle M = 125°, m = 12.4 and l = 7.6
We will use The Law of Sines to find angle L first:
sin(L)/l = sin(M)/m
sin(L)/7.6 = sin(125°)/12.4
sin(L) = (7.6×sin(125°))/12.4
sin(L) = 0.5020...
L = 30.136...°
L = 30.1° to one decimal place
Next, we will use "the three angles add to 180°" to find angle N:
N = 180° − 125° − 30.136...°
N = 24.863...°
N = 24.9° to one decimal place
Now we will use The Law of Sines again to find n:
n/sin(N) = m/sin(M)
n/sin(24.863...°) = 12.4/sin(125°)
n = (sin(24.863...°)×12.4)/sin(125°)
n = 6.36 to 2 decimal places
Note there is only one answer in this case. The "12.4" line only joins up one place.
The other possible answer for L is 149.9°. But that is impossible because we already have M = 125° and a triangle can't have two angles greater than 90°.
Conclusion:
When solving a "Side, Side, Angle" triangle we need to
check if there could be another possible answer!
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Source: https://www.mathsisfun.com/algebra/trig-solving-ssa-triangles.html